Three angles of a quadrilateral are (3x - 10), 2x and (2x + 10) and the fourth angle measures 80°. Find
the measure of the remaining angles of the quadrilateral
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Answer:
x = 40
Step-by-step explanation:
(3x - 10)° + 2x + (2x + 10)° +80° = 360°
3x + 2x + 2x = 360° -80°
7x = 280
x= 280/7
x = 40
3x+10= 3X40 - 10 = 110°
2x = 2X40 = 80
2x+10= 2X40 - 10 = 90°
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