Three angles of a quadrilateral are 50° 70 °and 100°, then the fourth angle is
We know, by angle sum property, the sum of angles of a quadrilateral is 360
o
.
The given angles are, 70°,95°,105°
Let the fourth angle be x°
Then, 70°+95°+105+x°=360°
⇒ 360°- (70°+95°+105°)=x∘
⇒ x°=360°−270°
=90∘
Therefore, the fourth angle is x°=90°
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Three angles of a quadrilateral are 50° 70 °and 100°, then the fourth angle is
We know, by angle sum property, the sum of angles of a quadrilateral is 360
o
.
The given angles are, 70°,95°,105°
Let the fourth angle be x°
Then, 70°+95°+105+x°=360°
⇒ 360°- (70°+95°+105°)=x∘
⇒ x°=360°−270°
=90∘
Therefore, the fourth angle is x°=90°
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