Three angles of a quadrilateral are equal and the measure of the fourth angle is 120°. Find the measure of each of the equal angles.
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let the equal angles be x
x + x + x + 120° = 360° [ ASP of quadrilaterals]
3x + 120 = 360
3x = 360 - 120
3x = 240
x = 240 / 3
x = 80°
Therefore each of the equal angles are 80°
x + x + x + 120° = 360° [ ASP of quadrilaterals]
3x + 120 = 360
3x = 360 - 120
3x = 240
x = 240 / 3
x = 80°
Therefore each of the equal angles are 80°
Answered by
3
❤️HEY MATE ❤️
We know that sum of the angles of quadrilateral is 360
Given:
Three angles are equal
Fourth angle=120
SOLUTION :
Let the unknown angle be x
Hence, the three angles are x
So,
x + x + x +120 =360
3x +120=360
3x =360-120
3x=240
x=240/3=80
Hence, the measure of equal angles is 80
We know that sum of the angles of quadrilateral is 360
Given:
Three angles are equal
Fourth angle=120
SOLUTION :
Let the unknown angle be x
Hence, the three angles are x
So,
x + x + x +120 =360
3x +120=360
3x =360-120
3x=240
x=240/3=80
Hence, the measure of equal angles is 80
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