Question

Three angles of a quadrilateral are in the ratio
2:6: 4. The difference of the least and the
greatest of angles out of these angles is the fourth
angle. Find all the angles of the quadrilateral.​

Answer 1

Step-by-step explanation:

Let the numbers be 2x, 6x and 4x

And let the fourth side be = 2x - 6x = 4x

So;

=> 2x + 6x + 4x + 4x = 360° ( as the sum of all the sides of the quadrilateral is 360°)

=> 16x = 360

=> x = 360 / 16

= x = 22.5

Then;

(2*22.5) (6*22.5) (4*22.5) (4*22.5)

= 45°, 135°, 90°, 90°

Hence the angles of the quadrilateral are 45°, 135°, 90°, 90°

HOPE IT HELPS

Answer 2

Answer:

the total angel of the quadrilateral is 360.

the sum of the total ratio of the angle is 2:6:4=>2+6+4=>12.

so first angle is 360×2/12.=>720/12=>60.

second angle is 360×6/12.=>360/2.=>180.

third angel is 360×4/12.=> 360/3. => 120.

so forth angle is 60+120+180+?=>360

360+?=>360

?=>360-360

?=>0.

so forth angle is 0.

Hopes its help u mark it as a brainlist answer.