Question

Three angles of a quadrilateral are in the ratio 2:6:4. The difference of the least and the greatest of angles out of these angles is the four angle. Find all the angles of the quadrilateral..

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Answer 1

Answer:

Sum of all angles of quadrialteralis360

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⇒2x+6x+4x+P=360

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⇒12x+P=360

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→(i)

let atleast angle is2x and greatest angle is 6x,

Their difference(−2x+6x)=P,4x=P

⇒from equation,12x+4x=360

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,16x=360

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,x=22.5

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⇒∴∠A=2x=2×5=45,∠B=6x=135,∠C=90

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,∠D=90

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Step-by-step explanation:

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Answer 2

see the attachment.... plz