Three angles of a quadrilateral are in the ratio 2:6:4 the difference of the least and the greatest of angles out of these angles is the fourth angle find all the angles of the quadrilateral
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⇒Sumofallanglesofquadrialteralis360
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⇒2x+6x+4x+P=360
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⇒12x+P=360
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→(i)
letatleastangleis2xandgreatestangleis6x,
Theirdifference(−2x+6x)=P,4x=P
⇒fromequation,12x+4x=360
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,16x=360
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,x=22.5
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⇒∴∠A=2x=2×5=45,∠B=6x=135,∠C=90
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,∠D=90
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