Three angles of a quadrilateral are in the ratio 3:4:5. The difference between the least and the greatest of these angles is 45. Find all the four angles of the quadrilateral.
Answers
Answer:
the angles are 67.5°, 90°, 112.5°, and 90°
Step-by-step explanation:
Let the three angles be 3x, 4x, 5x
It’s is given that
5x - 3x = 45
=> 2x = 45
=> x = 22.5
Therefore the 3 angles are
3*22.5 = 67.5
4*22.5 = 90
5*22.5 = 112.5
According to Angle Sum Property Of Quadrilaterals,
The sum of the 4 angle of a quadrilateral = 360
Let the 4th angle be y
67.5 + 90 + 112.5 + y = 360
=> y = 360 - 270 = 90
Therefore, the angles are 67.5°, 90°, 112.5°, and 90°
Please brainlist my answer, if helpful!
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Answer:
45°, 60° , 75°
Step-by-step explanation:
let's take:-)
1st angle as 3x
2nd angle as 4x
3rd angle as 5x
we know that sum of all angles of a triangle is 180°
therefore,
3x + 4x + 5x = 180
12x = 180
transposing 12
X = 180/12
X = 15
1st angle = 3x = 3(15)= 45°
2nd angle = 4x = 4(15) = 60°
3rd angle = 5x = 5(15)= 75°