Question

Three angles of a quadrilateral are in the ratio 4:5:3. The difference of the least and the greatest of these angles is 42'. Find all the four angles of the quadrilateral.

Answer 1

Let the 4th angle =x
So 3rd angle=3x
2nd angle =5x
1st angle =4x
So 5x-x=42
X=8
So then x=8°
3x=3×8=24°
5x=5×8=40°
4x=4×8=32°

Answer 2

Answer:

108degree

Step-by-step explanation:

Let common ratio be 'x'

therefore the angles of quadrilateral are 4x , 5x and 3x.

According to the condition:

5x - 3x =42

therefore , x=21

therefore the angles of quadrilateral are

4x = 4 x 21 = 84degree

5x = 5 x 21 = 105degree

3x = 3 x 21 = 63degree

the 4th angle of a quadrilateral = 360 - (84degree + 105degree + 63degree) sum of all angle = 108degree