Question

Three angles of a quadrilateral are in the ratio 4:5:3the difference of the least and the greatest of these angles is 42find all the four angles of the quadrilateral.

Answer 1

Let the angles of quadrilateral are 4x, 5x and 3x.

5x - 3x = 42

2x = 42

x = 42 / 2 = 21

Hence angles of quadrilateral are

4x = 4*21 = 84

5x = 5*21 = 105

3x = 3*21 = 63

Since sum of all the angles of quadrilateral are 360

So let the fourth angle be d.

84 + 105 + 63 + d = 360

d = 360 - 252

d = 108

All four angles are 84, 105, 63 and 108.


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