Question

Three angles of a quadrilaterals are in the ratio 3: 2: 1 and the fourth angle is 60°. What is the value of biggest angle?
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Answer 1

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150°

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Let the angles be 3x 2x and x

By angle sum of quadrilateral

3x+2x+x+60°=360°

6x+60°=360°

6x=360°-60°

6x=300°

x=300°/6=50°

Therefore angles are 3x=150° ,2x=100° x=50°

Value of biggest angle is 150°

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Answer 2

★Answer :-

• 150° is the value of biggest angle .

★Step-by-step-Explaination :-

★Given :-

• Three angles of a quadrilateral are in the ratio 3 : 2 : 1 .
• Fourth angle = 60° .

★Find :-

• Value of the biggest angle ?

★Let :-

• Let the first angle of a triangle be x .
• Let the second angle of a triangle be 2x .
• Let the third angle of a triangle be 3x .

Then ,

★We know that :-

• Sum of 4 angles of a Quadrilateral is 360°.

Then ,

★Equation becomes :-

$\rm \: x + 2x + 3x + 60° = 360°$

★Solution :-

$\rm \: x + 2x + 3x + 60° = 360°$

Let's add all x together ,

$\rm \: : : \implies 6x + 60°= 360°$

Now , 60° will be brought to R.H.S and being Substracted ,

$\rm \: : : \implies 6x = 360° - 60°$

So , after the difference left is

$\rm \: : : \implies 6x = 300°$

Now , x will remain in L.H.S only and 6 will be brought to R.H.S and being divided as because it is multiplied in L.H.S ,

$\rm \: : : \implies x = \dfrac{ 300° }{6}$

So , value of x becomes :-

$\rm \: : : \implies \bf x = 50°$

Therefore ,

• $\rm \: First \: angle \longrightarrow \: x = \underline{\bf50°}$
• $\rm \: Second \: angle \longrightarrow \: 2x = 2 \times 50° = \underline{\bf100°}$
• $\rm \: Third \: angle \longrightarrow3x = 3 \times 50° = \underline{\bf150°}$
• $\rm \: Fourth \: angle \longrightarrow \bf60°$

Therefore , Value of the biggest angle is 150° .

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