Question

Three angles of a triangle are ( 2x + 20)0 , ( x + 30 )0 and ( 2x – 10) . Find the angles.​

Answer 1

Answer:

required angles are 76°, 58°, 46°

Step-by-step explanation:

Three angles of a triangle are ( 2x + 20)0 , ( x + 30 )0 and ( 2x – 10)

sum of Three angles of a triangle =180°

(2x + 20)° + ( x + 30 )°+ ( 2x – 10)° = 180°

5x + 40°= 180°

5x = 180° - 40°

5x= 140°

X = 140°/5

X = 28°

( 2x + 20)°= 2×28°+20°= 56°+20°= 76°

( x + 30 )°= 28°+30°= 58°

and ( 2x – 10)°= 2×28°-10°=56°-10 = 46°

required angles are 76°, 58°, 46°