Question

Three angles of a triangle are in the ratio 1:2:1. Find all the angles of the triangle. Classify the triangle in two different ways.


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Answer 1

Step-by-step explanation:

Let the angles of the triangles be x,2x\:\:and\:\:x

Let the angles of the triangles be x,2x\:\:and\:\:xSo,

Let the angles of the triangles be x,2x\:\:and\:\:xSo, As we know the sum of internal angles of a triangle is 180. so,

Let the angles of the triangles be x,2x\:\:and\:\:xSo, As we know the sum of internal angles of a triangle is 180. so,x+2x+x=180^0

Let the angles of the triangles be x,2x\:\:and\:\:xSo, As we know the sum of internal angles of a triangle is 180. so,x+2x+x=180^04x=180^0

Let the angles of the triangles be x,2x\:\:and\:\:xSo, As we know the sum of internal angles of a triangle is 180. so,x+2x+x=180^04x=180^0x=45^0

Let the angles of the triangles be x,2x\:\:and\:\:xSo, As we know the sum of internal angles of a triangle is 180. so,x+2x+x=180^04x=180^0x=45^02x=90^0

Let the angles of the triangles be x,2x\:\:and\:\:xSo, As we know the sum of internal angles of a triangle is 180. so,x+2x+x=180^04x=180^0x=45^02x=90^0Hence the angles of the triangles are 45^0,90^0\:\:and\:\:45^0.

Let the angles of the triangles be x,2x\:\:and\:\:xSo, As we know the sum of internal angles of a triangle is 180. so,x+2x+x=180^04x=180^0x=45^02x=90^0Hence the angles of the triangles are 45^0,90^0\:\:and\:\:45^0.On the Basis of sides, the triangle is isosceles triangle as two sides of the triangle are equal.

Let the angles of the triangles be x,2x\:\:and\:\:xSo, As we know the sum of internal angles of a triangle is 180. so,x+2x+x=180^04x=180^0x=45^02x=90^0Hence the angles of the triangles are 45^0,90^0\:\:and\:\:45^0.On the Basis of sides, the triangle is isosceles triangle as two sides of the triangle are equal.On the Basis of angle, the triangle is Right-Angled Triangle as it has one angle equal to 90 degrees.