Three angles of a triangle are x°,(x+10)° and 70°. Find the two angles of the triangle.
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Answered by
3
Given , 1st ang. = 70°
2nd ang. = x
3rd ang. = x + 10
So , By Angle sum property ,
1st ang. + 2nd ang. + 3rd ang. = 180°
70° + x + x + 10 = 180
80° + 2x = 180°
x = 50°
Hence the other angles are :
2nd ang. = x = 50°
3rd ang. = x + 10 = 50 + 10 = 60°
2nd ang. = x
3rd ang. = x + 10
So , By Angle sum property ,
1st ang. + 2nd ang. + 3rd ang. = 180°
70° + x + x + 10 = 180
80° + 2x = 180°
x = 50°
Hence the other angles are :
2nd ang. = x = 50°
3rd ang. = x + 10 = 50 + 10 = 60°
Answered by
1
The sum of three angles of a triangle = 180
Hence x+x+10+70 = 180
2x+80 = 180
x = 50
Two angles are 50 and 60.
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