Three angles of quadrilateral are in the ratio 1 5 6 the mean of these angles is 64 degree find the fourth angle
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As we know,
⇒Sum of all angles of quadrialteralis 360
⇒2x+6x+4x+P=360
⇒12x+P=360
→(i) let atleast angle is 2x and greatest angle Is 6x,
Their difference (−2x+6x) = P,4x = P
⇒from equation,12x+4x=360
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,16x=360
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,x=22.5
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⇒∴∠A=2x=2×5=45,∠B=6x=135,∠C=90
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,∠D=90
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