Question

three bag contains 64.2 kg of sugar the second bag contains 4 by 5 of the constants of the first and the third bag contains 45.5 %
is the second bag how many sugar in there is of the bag ​

Answer 1

Answer:

1st bag =62.2kg,2nd bag =12.85kg 3rd bag=4.76kg

Answer 2

Answer:

Step-by-step explanation:

3 bags of sugar weight=64.2 kg

let the first bag of sugar weight be x kg,

2nd bag weight= 4x/5=0.8x

3rd bag weight= 45.5%*0.8x=0.455*0.8=0.364x

Therefore, weight of 1st bag= x+0.8x+0.364x

                                            64.2=2.164x

                                          64.2/2.164=x

                                          64200/164=x

                                 (approx.)29.67=x

                         2nd bag weight= 0.8*29.67=23.736kg

                     3rd bag weight=0.455*23.736=10.789886kg=10.789kg=10.8kg

                           

hope this helps.