Three bags contain 3 red, 7 black;8 red, 2black, and 4 red and 6 black balls respectively. 1 of the bags is selected at random and a ball is drawn from it. If the ball drawn is red, find the probability that it is dream from the third bag.
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Answer:
Total number of balls in the third bag = 10
Favourable number of ball = 1 ( i.e, red )
Therefore, P(E) = 1/10
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