Question

three balanced coins are tossed together then is the probability that at most two hand comes up​

Answer 1

When three coins are tossed together, the total number of outcomes =8

i.e., (HHH,HHT,HTH,THH,TTH,THT,HTT,TTT)

Solution (i):

Let E be the event of getting exactly two heads

Therefore, no. of favorable events, n(E)=3(i.e.,HHT,HTH,THH)

We know that, P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

8

3