Three ball A B and c are kept in a straight line the separation between A and C is 1m B is placed at the midpoint between them the masses of A B C masses are 100g 200g and 300g respectively find out the net gravitational force on a b and c
Answers
The net gravitational force on a = 7.34 x 10⁻¹² N , b = 1.07 x 10⁻¹¹ N and c = 7.34 x 10⁻¹² N respectively.
Explanation:
A ------ 0.50 m -------- B -------- 0.50 -------- C
Ma = 0.100 kg Mb = 0.200 kg Mc = 0.300 kg
- Net gravitational force Fa on A is towards right side.
Fa = G Ma Mb / 0.50² + G Ma Mc / 1.0²
= 6.67 x 10⁻¹¹ x 0.100 [ 0.200/ 0.50² + 0.300 /1 ] N
= 7.34 x 10⁻¹² N
- Net gravitational force Fc on C is towards B, left side and its magnitude is equal to Fa i.e. 7.34 x 10⁻¹² N
- Net gravitational force on B is Fb & is towards C
Fb = G Mb [ Mc - Ma ]/ 0.50²
= 6.67 x 10⁻¹¹ x 0.200 x 0.200 x 4 = 1.07 x 10⁻¹¹ N
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A mass of 10 kg is at a point A on a table. It is moved to a point B. If the line joining A and B is horizontal, what is the work done on the object by the gravitational force?
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Answer:
Explanation:
A ------ 0.50 m -------- B -------- 0.50 -------- C
Ma = 0.100 kg Mb = 0.200 kg Mc = 0.300 kg
Net gravitational force Fa on A is towards right side.
Fa = G Ma Mb / 0.50² + G Ma Mc / 1.0²
= 6.67 x 10⁻¹¹ x 0.100 [ 0.200/ 0.50² + 0.300 /1 ] N
= 7.34 x 10⁻¹² N
Net gravitational force Fc on C is towards B, left side and its magnitude is equal to Fa i.e. 7.34 x 10⁻¹² N
Net gravitational force on B is Fb & is towards C
Fb = G Mb [ Mc - Ma ]/ 0.50²
= 6.67 x 10⁻¹¹ x 0.200 x 0.200 x 4 = 1.07 x 10⁻¹¹ N
Also learn more
A mass of 10 kg is at a point A on a table. It is moved to a point B. If the line joining A and B is horizontal, what is the work done on the object by the gravitational force?