Question

Three balls a b c are of masses m,2m, 3m respectively and are placed on a smooth horizontal surface

Answer 1

Explanation:

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Answer 2

Answer:

For collision between B and C

vg=(m1-em2m1+m2)u1+m2(1+e)(m1+m2)u2

=(m-4m5m)v+0=-3/5v

vC=m1(1+e)(m1+m2)u1+(m2-em1m1+m2)v2=m(1+1)4mv+0=v2

For collsion between A and B :

vA=0+m(1+1)5m×(3v5)=625v

vB=0+(m-4m5m)(-3v5)=9v25

∵vB<vC

∵ B will not collide with C

Therfore there will be only two collision.