Question

Three balls are drawn at random from a bag containing 6 blue and 4 red balls. What is the chance that 2 balls are blue and 1 is red?

Answer 1

Our required probability is 0.5.

Step-by-step explanation:

Since we have given that

Number of blue balls = 6

Number of red balls = 4

Total number of balls = 10

Number of balls to be drawn = 3

We need to find the probability that 2 balls are blue and 1 is red.

So, Probability would be

$\dfrac{^6C_2\times ^4C_1}{^{10}C_3}}\\\\=\dfrac{60}{120}\\\\=\dfrac{1}{2}=0.5$

Hence, our required probability is 0.5.

# learn more:

A bag contains 4 white, 5 red and 6 green ball. three balls are drawn at random. the chance that a whote a green and a red ball will be

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