three balls are drawn from a bag containing 2 red and 5 black balls, if the random variable X represents the number of red balls drawn, then X can take values
Answers
Answer:NSWER
Uru has 5 red and 2 black balls
No. of ways it can be drawn ={RR,RB,BR,BB}
n(S)=4
LEt X represent black balls
Possible values of X:X(RR)=0;X(RB)=1;X(BR)=1;X(BB)=2
Possible values of X are 0,1,2
P(X=0=
4
1
,P(X=2)=
4
2
,P(X=2)=
4
1
∑P
i
x
i
=P(X=0)+P(X=1)+P(X=2)=
4
1
+
4
2
+
$
1
=1
X is a random variable
Now, P(X=0=P(No black)
=
7
C
2
5
C
2
=
42
20
P(X=1)=P(1 black ball)=
7
C
2
5
C
1
×
2
C
1
=
42
20
P(X=2)=P(2 black balls)=
7
C
2
2
C
2
=
42
2
X=0;P(X=x)=
42
20
X=1;P(X=x)=
42
20
Step-by-step explanation:
Answer:
The possible values on X that is red balls drawn is 0,1,2,3,4,5,6
Step-by-step explanation:
What is probability?
- The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.
- There are four primary categories of probability: axiomatic, classical, empirical, and subjective.
Given that,
B bag has 2red and 5 black balls
No. of possible ways it can drawn is :{RRB,RBR,BRR,RBB,BRR,BRB,BBR,BBB}
n(S) = 8
Here X represent red balls
Possible values of X : X(RRB)=0;X(RBR) = 1;X(BRR) = 2;X(RBB) =3; X(BRR) = 4 ; X(BRB) = 5; X(BBR)=6
Therefore possible values of X are 0,1,2,3,4,5,6.
To learn more about probability refer to :
https://brainly.com/question/24756209
https://brainly.in/question/16017018
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