Question

Three balls are drawn successively from the box of containing 6 red balls , 4 white balls , and 5 blue balls . Find the probability that they are drawn in order red ,white, and blue if each ball is not replaced ?​

Answer 1

Answer:

probability

$\frac{1}{15}$ = 0.6%

Answer 2

Answer:

4/91

Step-by-step explanation:

Probability that they are drawn in order red ,white, and blue if each ball is not replaced

$= \frac{6}{15} \times \frac{4}{14} \times \frac{5}{13} \\ \\ = \frac{2 \times 2 \times 5}{5 \times 7 \times 13} \\ \\ = \frac{2 \times 2}{7 \times 13} \\ \\ = \frac{4}{91}$