THREE BALLS RING AT INTERVALS OF 12,15 AND 21 MINUTES IF THEY RING SIMULANTANEOUSLY AT 9 AM THEN NEXT
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Answer:
4 PM
Step-by-step explanation:
PART 1
LCM of three numbers must be taken.
Let us use prime factorization in this case
• Write out the prime factors of each number
12: 2 x 2 x 3
15: 3 x 5
21: 3 x 7
•Cancel out the common factors
We will be left with:
2 x 2 x 3 x 5 x 7
• Multiply the remaining factors
2 x 2 x 3 x 5 x 7 = 420
:- 420 minutes
PART 2
• Convert minutes to hours
420/60
= 7
• Add the hours to the final time
9 AM + 7 hours
= 16 hours
= 4 PM
«» The three bells will ring simultaneously at 4 pm
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