three baskets of fruits contain 42,98,and 70 pieces respectivy. what is the highest common number of fruits that can be taken from all three baskets at on given point
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Hello ,
The answer you require is here...
Factors of 42 = 2×3×7
Factors of 98 = 2×7×7
Factors of 70 = 2×5×7
Here the common factors are
2 and 7
So, the HCF is 2×7 = 14
So, 14 is the highest common number of fruits that can be taken from all the baskets.
Hope it helps u... :-)
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The answer you require is here...
Factors of 42 = 2×3×7
Factors of 98 = 2×7×7
Factors of 70 = 2×5×7
Here the common factors are
2 and 7
So, the HCF is 2×7 = 14
So, 14 is the highest common number of fruits that can be taken from all the baskets.
Hope it helps u... :-)
Please Mark it as the BRAINLIEST
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