Question

three batteries of emf and internal resistance 1 ohm each are connected as shown effective emf of combination between the points pq is​

Answer 1

Given:

Three batteries of emf and internal resistance 1 ohm each are connected as shown.

To find:

Effective EMF of the combination between the points P and Q .

Calculation:

We can see that the three batteries are connected in series combination with same polarities.

Hence , the effective EMF will be algebric addition of the individual EMF of the batteries.

$\rm{E_{eff.} = E_{1} + E_{2} + E_{3}}$

$= > \rm{E_{eff.} = E+ E+ E}$

$= > \rm{E_{eff.} =3 E}$

Similarly , the internal resistance of the batteries are in series combination.

$\rm{R_{eff.} = R_{1} + R_{2} + R_{3}}$

$= > \rm{R_{eff.} = 1 + 1 + 1}$

$= > \rm{R_{eff.} = 3 \: ohm}$

So, final answer is:

Effective EMF is 3E and effective internal resistance is 3 ohm.