Question

Three bells are ringing continuously at intervals of 30,36 and 45 minutes respectively. At what time will they ring together again if they ring simultaneously at 8 a.m.?

Answer 1

find the least common multiple of 30,36 and 45
3 |30,36,45
5 |10,12,15
3 |2,12,3
2 |2,4,1
2 |1,2,1
|1,1,1 So L.C.M. of 30,36 and 45 is 3×5×3×2÷2=180.
So after 180 minutes they ring together Therefore they all ring together at 11:00 a.m. Hope it helps you...

Answer 2

Answer:

11 a.m.

Step-by-step explanation:

We are given that Three bells are ringing continuously at intervals of 30,36 and 45 minutes respectively.

Si, First Find the least common multiple of 30,36 and 45

3 |30,36,45

5 |10,12,15

3 |2,12,3

2 |2,4,1

2 |1,2,1

  |1,1,1

So L.C.M. of 30,36 and 45 is $3 \times 5\times3\times2\times2=180.$

So after 180 minutes they ring together .

60 minutes = 1 hour

So, 180 minutes = 3 hours

So, after 3 hours they ring together.

Therefore they all ring together again if they ring simultaneously at 8 a.m. at 11:00 a.m.