three bells commence tolling simultaneously if tearing at an interval of 40 second 48 second and 50 second respectively if there and together at 7 a.m. at what time will they rang together again
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First of all, we have to find d the LCM [ Least Common Multiple ] of the given components i.e 40, 48, 50 .
And add it to the 1st time they all rang i.e 7 a.m
LCM of 40, 48, 50 = 120
120 mins ÷ 60 = 2 hours
So, next time that they all ring together = 7 a.m + 2hrs = 9 a.m
Solution : 9 a.m
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hey watch the above pic for ur answer .
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