Math, asked by rajveer9372, 8 months ago

three bells commence tolling simultaneously if tearing at an interval of 40 second 48 second and 50 second respectively if there and together at 7 a.m. at what time will they rang together again

Answers

Answered by vasanthaallangi40
1

First of all, we have to find d the LCM [ Least Common Multiple ] of the given components i.e 40, 48, 50 .

And add it to the 1st time they all rang i.e 7 a.m

LCM of 40, 48, 50 = 120

120 mins ÷ 60 = 2 hours

So, next time that they all ring together = 7 a.m + 2hrs = 9 a.m

Solution : 9 a.m

HOPE, IT'LL HELP YOU

KEEP SMILING

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Answered by THEGOODBOY90
9

Answer:

hey watch the above pic for ur answer .

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