Math, asked by susmita5065, 8 days ago

Three bells ring at intervals of 12 ,15 and 18 seconds respectively. if they starts ringing together at 8:35 a.m, at what time they ring together again at the earliest?

Answers

Answered by PrathamSGowda

Step-by-step explanation:

ʜɪ ɢᴜʏꜱ

ᴍʏꜱᴇʟꜰ ᴘʀᴀᴛʜᴀᴍ

ɪ ɴᴇᴇᴅ ʙᴇꜱᴛ ꜰʀɪᴇɴᴅ

ɪꜰ ᴀɴʏᴏɴᴇ ɪɴᴛᴇʀᴇꜱᴛᴇᴅ

ᴘʟꜱ ᴍꜱɢ ᴍᴇ

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ᴘʟꜱ ɢᴜʏꜱ

ɴᴏᴛ ꜰᴏʀ ʙᴀᴅ ᴛʜɪɴɢꜱ

ᴏɴʟʏ ꜰᴏʀ ꜰʀɴᴅꜱʜɪᴘ

Answered by jiakher84

180 is common in 12, 15 and 18. Therefore, LCM of 12, 15 and 18 is 180. Given : They started ringing together at 8:35 a.m. Second time they ringing together = 8:35 + 180 seconds = 8:35 + 3 minutes = 8.38 a.m

Hope it helps you sakhi!

Radhe Radhe

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Three bells ring at intervals of 12 ,15 and 18 seconds respectively. if they starts ringing together at 8:35 a.m, at what time they ring together again at the earliest?​

Answers

Three bells ring at intervals of 12 ,15 and 18 seconds respectively. if they starts ringing together at 8:35 a.m, at what time they ring together again at the earliest?