Math, asked by susmita5065, 1 month ago

Three bells ring at intervals of 12 ,15 and 18 seconds respectively. if they starts ringing together at 8:35 a.m, at what time they ring together again at the earliest?

Answers

Answered by PrathamSGowda

Step-by-step explanation:

ʜɪ ɢᴜʏꜱ

ᴍʏꜱᴇʟꜰ ᴘʀᴀᴛʜᴀᴍ

ɪ ɴᴇᴇᴅ ʙᴇꜱᴛ ꜰʀɪᴇɴᴅ

ɪꜰ ᴀɴʏᴏɴᴇ ɪɴᴛᴇʀᴇꜱᴛᴇᴅ

ᴘʟꜱ ᴍꜱɢ ᴍᴇ

9141412673

ᴘʟꜱ ɢᴜʏꜱ

ɴᴏᴛ ꜰᴏʀ ʙᴀᴅ ᴛʜɪɴɢꜱ

ᴏɴʟʏ ꜰᴏʀ ꜰʀɴᴅꜱʜɪᴘ

Answered by jiakher84

180 is common in 12, 15 and 18. Therefore, LCM of 12, 15 and 18 is 180. Given : They started ringing together at 8:35 a.m. Second time they ringing together = 8:35 + 180 seconds = 8:35 + 3 minutes = 8.38 a.m

Hope it helps you sakhi!

Radhe Radhe

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Three bells ring at intervals of 12 ,15 and 18 seconds respectively. if they starts ringing together at 8:35 a.m, at what time they ring together again at the earliest?​

Answers

Three bells ring at intervals of 12 ,15 and 18 seconds respectively. if they starts ringing together at 8:35 a.m, at what time they ring together again at the earliest?