Math, asked by arpitadeshmukh81, 6 months ago

Three bells ring at intervals of 6,8 and 20 minutes. They ring simultaneously at 8 am. At what time will they ring together

Answers

Answered by as045668
4

Step-by-step explanation:

The L.CM of 6,8,20 is= 120

120minutes =2 hours (8am+2)=10am answer✓✓✓✓

Answered by dualadmire
0

The bells will again ring together at 10 AM.

Given: The three bells ring at intervals of 6,8 and 20 minutes. They ring simultaneously at 8 am.

To Find: The time they will ring together.

Solution:

Whenever we are asked to find the time the bells will ring together, we need to find their LCM.

We are given times as 6 min, 8 min, and 20 min. So, the respective prime factorization is,

6 = 2 × 3

8 = 2 × 2 × 2

20 = 2 × 2 × 5

Hence, the LCM = 2 × 2 × 2 × 3 × 5

                           = 120 min

So, we understand that the bells will again ring together after 120 min.

We know that 120 min = 2 hrs and the bells simultaneously rang at 8 am,

So, they will again ring after = ( 8 + 2 ) AM = 10 AM

Hence, the bells will again ring together at 10 AM.

#SPJ2

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