Three bells ring up with the time intervals of 48,60and90 min.If all three ring up at 10:00 am together,then at what time,they all will ring up again on the same day
Answers
Answered by
28
To find this , we have to find LCM of all these
48 = 2 × 2 × 2 × 2 × 3
60 = 2 × 2 × 3 × 5
90 = 2 × 3 × 3 × 5
so , LCM = 2 × 3 × 2 × 5 × 2 × 2 × 3
LCM = 720 minutes
so after 720 minutes they all will ring up again .
720 minutes = 12 hours
12 hours after 10 .00 am ,
i.e. at 10.00 pm
48 = 2 × 2 × 2 × 2 × 3
60 = 2 × 2 × 3 × 5
90 = 2 × 3 × 3 × 5
so , LCM = 2 × 3 × 2 × 5 × 2 × 2 × 3
LCM = 720 minutes
so after 720 minutes they all will ring up again .
720 minutes = 12 hours
12 hours after 10 .00 am ,
i.e. at 10.00 pm
piku3884:
answer options mey nahi hai
480 mins = 8 hours so 10 am + 8= 6 pm
little mistake
sir answer 10:am hoga
720 minutes into 60 hoga
report my answer , so that i can make change in that
Similar questions