Three bells ring with a time gap of 10 min. 20 min and 30 respectively in a school. If all bells are rung together at 8:00 am after how long the bells would ring together again?
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Step-by-step explanation:
In a simple way, we need to find the lowest number, which is fully divisible by 10,15 and 20. So we should find the PCM of these numbers
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