three bells toll at interval of 12m 15m and 18m respectivily.if they start tolling together what time will they next toll together
Answers
Answered by
3
Given that three bells toll at the interval of 12m,15m, and 18m.
12 = 2 * 2 * 3
15 = 3 * 5
18 = 2 * 3 * 3
LCM of 12,15,18 = 2 * 2 * 3 * 3 * 5
= 180.
Therefore they will next toll together at 180 minutes (or) 3 hours.
Hope this helps!
12 = 2 * 2 * 3
15 = 3 * 5
18 = 2 * 3 * 3
LCM of 12,15,18 = 2 * 2 * 3 * 3 * 5
= 180.
Therefore they will next toll together at 180 minutes (or) 3 hours.
Hope this helps!
siddhartharao77:
Okk sonu. solve it
Actually u wrote Lcm of 12 = 2×2×3
but it was simply 12 = 2×2×3
Hope bhaiya now u know
If u write Lcm here it becomes wrong
Ohkkk. Now i got it. Thanks sonu.
U r sooooo good that I am following u
bye
Thanks sonu for the valuable suggestion.
Bye
Answered by
3
Hi,
Here's ur answer:-
12 = 2×2×3
15=3×5
18=2×3×3
LCM = 2×2×3×3×5 = 180.
So, they will ring after 180 mins.
HOPE IT HELPS (^_^)
Here's ur answer:-
12 = 2×2×3
15=3×5
18=2×3×3
LCM = 2×2×3×3×5 = 180.
So, they will ring after 180 mins.
HOPE IT HELPS (^_^)
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