Three blocks A, B and C are kept as shown in the figure. The coefficient of friction for each surface of contact is given. A horizontal force F0 = 60 N acts on block A at t = 0. The acceleration of A w.r.t C at t = 0 is (g = 10 m/s2)

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Explanation:
draw FBD of top block (10 kg) and the middle block (20 kg)
on block one there is hundred Newton force due to gravity let the normal reaction on block b n then it will exert n onto the middle block
so if we apply net force balance on block top block then n is equal to hundred and maximum frictional force between top block and middle block is 0.6 *n and which is is 60 Newton
show the maximum frictional force is equal to the applied force hence there will be no displacement
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