Question

Three blocks A, B and C having masses 3kg, 2kg
and x kg respectively are attached by massless
strings and ideal pulleys as shown in figure. When
the system is released from rest if the block C
remaining stationary, the mass of block C is​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Mass\:of\:block\:C\approx1.6\:kg}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Mass \: of \: block \: A = 3 \: kg \\ \\ \tt: \implies Mass \: of \: block \: B = 2 \: kg \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Mass \: of \: block \: C = ?$

• According to given question :

$\bold{For \: block \: A} \\ \tt: \implies T-mg= ma \\ \\ \tt : \implies 2T - 3g = 3 \times \frac{a}{2} \\ \\ \tt: \implies 2T- 3g = \frac{3a}{2} - - - - - (1) \\ \\ \bold{For \: block \:B} \\ \tt: \implies mg - T= ma \\ \\ \tt: \implies 2g - T= 2a \\ \\ \tt: \implies 4g - 2T= 4a - - - - - (2) \\ \\ \text{Adding \: (1) \:and\: (2)} \\ \tt: \implies 4g - 3g = \frac{3a}{2} + 4a \\ \\ \tt: \implies g = \frac{3a + 8a}{2} \\ \\ \tt: \implies g = \frac{11a}{2} \\ \\ \tt: \implies a = \frac{2g}{11} \\ \\ \text{Putting \: value \: of \: a \: in \: (2)} \\ \tt: \implies 2g - T=2 \times \frac{2g}{11} \\ \\ \tt: \implies T= \frac{22g - 4g}{11} \\ \\ \tt: \implies T= \frac{18g}{11} \\ \\ \bold{For \: block \: C} \\ \tt: \implies t = mg \\ \\ \tt: \implies \frac{18g}{11} = mg \\ \\ \tt: \implies m = \frac{18g}{11g} \\ \\ \tt: \implies m = \frac{18}{11} \\ \\ \green{\tt: \implies m \approx 1.6 \: kg}$

Answer 2

$</p><p>\tt{\huge{\pink{Hello!!! }}}$

$</p><p>\tt{\purple{---------------}}$

$</p><p>\tt{\huge{\boxed {\boxed {\implies {\bullet{\purple{Question \: - }}}}}}}$

Three blocks A, B and C having masses 3kg, 2kg and x kg respectively are attached by massless strings and ideal pulleys as shown in figure.

When the system is released from rest if the block C remaining stationary, the mass of block C is ?

$</p><p>\tt{\purple{---------------}}$

$</p><p>\tt{\huge{\boxed {\boxed {\implies {\bullet{\purple{Solution \: - }}}}}}}$

For Block A :

$</p><p>\tt{\blue{T − mg = ma}}$

$</p><p>\tt{\red{2T−3g=3× 2a}} .......(1)$

For Block B :

For Block C :