Three blocks A, B and C of masses 4 kg, 2 kg and 1 kg respectively, are in contact on a frictionless surface, as shown. If a force of 14 N is applied on the 4 kg block then the contact force between A and B is (a) 6 N(b) 8 N(c) 18 N(d) 2 N
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Answer:
A) 6N
Explanation:
The acceleration due to force = 14N ( Given)
Mass A, B, C = 4 , 2 ,1 (Given)
When three blocks are in contact -
Fnet = ma
a = F/ m1+m2+m3
= 14/(4+2+1)
= 14/7
= 2m/s²
Thus, The contact force between A and B is used to move the bodies B and C only.
F = ma
F = (2+1)2
F = 3×2
=6N
Thus, the contact force between A and B is 6N.
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