Three blocks a b and c of masses 4kg 2kg and 1 kg are in contact on frictionlesss surface. If the force of 14n is applied on the block 4kg, then contact force between a and b is
Answers
Answered by
4
the acceleration due to force 14N=
F=ma
F/m =a
14/(4+2+1)
14/7
=2m/s2
the contact force between A and B is used to move the bodies B and C only.
F=ma
F=(2+1)2
F=3×2
=6N
if u have any doubt ask in answer box.
TQ!!!!!
Similar questions