Physics, asked by mansitewatia2737, 20 days ago

three blocks a b c placed on a smooth horizontal surface are being pushed with a force of 60N the contact force between block a and b is 30N and that between block b and c is 10N the ratio of masses of blocks a, b, c is

Answers

Answered by physicsbyhs
1

Answer:

3:2:1

Explanation:

Attachments:
Answered by DJANSUMAN99
1

Answer:

3:2:1

Explanation:

F = [ m(A) + m(B) + m(C) ] a

60 = [ m(A) + m(B) + m(C) ] a       ...... (i)

30 = [ m(B) + m(C) ] a      ..... (ii)

10 = m(C)*a                    ....... (iii)

From equation (ii) and (iii),

m(B) = 2m(C)           ...... (iv)

From equation (i) and (iii),

5m(C) = m(B) + m(A)         ...... (v)

Now, from equation (iv) and (v),

m(A) = 3m(C)

So,

      m(A): m(B): m(C) = 3m(C) : 2m(C) : m(C)

                                  = 3:2:1

                                          ... ANSWERR

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