three blocks a b c placed on a smooth horizontal surface are being pushed with a force of 60N the contact force between block a and b is 30N and that between block b and c is 10N the ratio of masses of blocks a, b, c is
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Answered by
1
Answer:
3:2:1
Explanation:
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Answered by
1
Answer:
3:2:1
Explanation:
F = [ m(A) + m(B) + m(C) ] a
60 = [ m(A) + m(B) + m(C) ] a ...... (i)
30 = [ m(B) + m(C) ] a ..... (ii)
10 = m(C)*a ....... (iii)
From equation (ii) and (iii),
m(B) = 2m(C) ...... (iv)
From equation (i) and (iii),
5m(C) = m(B) + m(A) ...... (v)
Now, from equation (iv) and (v),
m(A) = 3m(C)
So,
m(A): m(B): m(C) = 3m(C) : 2m(C) : m(C)
= 3:2:1
... ANSWERR
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