Question

three blocks are placed as shown in figure Mass of A B C are m1 m2 m3 respectively The force exerted by block C on B is

Answer 1

Given that mass of A, B and C are :

M₁, M₂ and M₃ respectively.

Force = Mg

Where g is the gravitational acceleration.

The force acting on C is :

(m₁ + m₂) g

According to Newton's third law of motion, for every action there is an equal and opposite reaction.

Therefore the force exerted by C on B is :

(m₁ + m₂) g

Answer 2

Answer:

Normal Force, N = (m₁ + m₂)g

Explanation:

[Refer to attached image 1 to visualize the case]

We know that, while finding normal force exerted by block C on B, we can add the masses of A and B and use them as a combined resultant mass as (A + B).

So, on drawing the free body diagram of the given case, we get;-

[Refer to the attached image 2 for F.B.D.]

Normal force, N= Resultant Mass × g   [Since, N= mg]

              N = (A + B) × g

              N = (m₁ + m₂) × g   [since, A = m₁ & B = m₂]

Hope it helps! ;-))