three blocks are placed as shown in figure Mass of A B C are m1 m2 m3 respectively The force exerted by block C on B is
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Answers
Given that mass of A, B and C are :
M₁, M₂ and M₃ respectively.
Force = Mg
Where g is the gravitational acceleration.
The force acting on C is :
(m₁ + m₂) g
According to Newton's third law of motion, for every action there is an equal and opposite reaction.
Therefore the force exerted by C on B is :
(m₁ + m₂) g
Answer:
Normal Force, N = (m₁ + m₂)g
Explanation:
[Refer to attached image 1 to visualize the case]
We know that, while finding normal force exerted by block C on B, we can add the masses of A and B and use them as a combined resultant mass as (A + B).
So, on drawing the free body diagram of the given case, we get;-
[Refer to the attached image 2 for F.B.D.]
Normal force, N= Resultant Mass × g [Since, N= mg]
N = (A + B) × g
N = (m₁ + m₂) × g [since, A = m₁ & B = m₂]
Hope it helps! ;-))
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