Question

Three blocks of different masses m,, mą, m, are connected as shown in figure
then the value of f12 and 123 is (where fi2 is the contact force between m, and m,
and f2, is contact force between m, and m3)​

Answer 1

Consider the three blocks as a single block of mass (m

1

+m

2

+m

3

) and a be the acceleration of the system.

So,(m

1

+m

2

+m

3

)a=F

⇒a=

(m

1

+m

2

+m

3

)

F

Now, net force on mass m

2

is F

2

=F

21

−F

23

Here, F

2

=m

2

a,

Also, F

32

=F

23

=m

3

a

Thus, we get:

m

2

a=F

21

−m

3

a