Question

Three blocks of mass 3 kg, 2 kg and 1 kg are placed side by side on a smooth surface as shown in figure. A horizontal force of 12 N is applied on 3 kg block. Then the net force on 2 kg block is


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Answer 1

Answer:

answer 4N

Explanation:

Given,

Mass=3kg,2kg,1kg f=12N

Since 12N is applied on the total mass =2+3+1=6kg

⇒a=

m

f

=

6

12

=2m/s

2

Therefore 2kg also moves with 2m/s

2

Thus the net force F

net

=m×a=2×2=4N