Three blocks of mass 3 kg, 5 kg and 8 kg connected through light strings are placed on a smooth horizontal
surface as shown below. The block of mass 3 kg is being pulled with a force of 40 N. [3]
Find :
(a) Acceleration of the blocks.
(b) Tension (T1) in the string connecting between 5 kg and 3 kg block.
(c) Tension (T2) in the string connecting between 5 kg and 8 kg block.
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Answer:
acceleration is 2.5m/s2
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The tension in the string is 12.5 N and 32.5 N respectively.
Explanation:
We are given that:
Mass of blocks = 3 kg, 5 kg and 8 kg
Force applied on block of mass 3 Kg = 40 N
To Find: Acceleration of block =?
Solution:
Acceleration = Force / Mass (total)
a = 40 / 16 = 2.5 m/s^2
Now tension "T2" = ma = 8 x 2.5 = 20 N
T1 - T2 = 5 x 2.5 = 12.5 N
T1 - 20 = 12.5 N
T1 = 12.5 + 20
T1 = 32.5 N
Thus the tension in the string is 12.5 N and 32.5 N respectively.
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