Three blocks of mass 3kg,2kg and 1kg are placed side by side on a smooth surface as shown in the figure. A horizontal force of 12N is applied on 3kg block the net force on 3 kg block, the acceleration of the system and net force n 3 kg block are
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Answer:
Correct option is
D
4N
Given,
Mass=3kg,2kg,1kg f=12N
Since 12N is applied on the total mass =2+3+1=6kg
⇒a=
m
f
=
6
12
=2m/s
2
Therefore 2kg also moves with 2m/s
2
Thus the net force F
net
=m×a=2×2=4N
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