Three blocks of mass 3kg, 2kg and 1kg placed side by side on a smooth surface as shown in fig.
A horizontal force of 12 N is applied on 3 Kg block. The net force on 3 Kg block. The acceleration
of the system and net force on 3kg block are
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Answered by
2
Answer:
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Answered by
5
Answer:
Given,
Mass=3kg,2kg,1kg f=12N
Since 12N is applied on the total mass =2+3+1=6kg
⇒a= f = 12 =2m/s²
m 6
∴ 2kg also moves with 2m/s²
Thus the net force F↓(net) =m×a=2×2=4N
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