Question

Three blocks of mass m1, m2 and m3 are connected as shown inthe figure. All the surfaces are frictionless and the string and thepulleys are light. Find the acceleration of m.​

Answer 1

Answer:

Explanation:

Hi!

Sorry but I think I may be wrong on this one pls cross-check

So m3 is moving downwards with  acc and T of rope is opposing its movement so

m3g-T=m3a (eq 1)

so m2 will be moving up as m3 is moving down.M2 is moving up due to Tension of rope and acc will act upwards {as rope is same tension of m3 and m2 will be same}

so 2nd eq is

T-m2g=m2a (eq2)

Combing them we get

m3g-m2g(T gets canceled out)=m2a+m3a

( a is the same)

(m3-m2)g=a(m2+m3)

(m3-m2)g/m2+m3=a

I hope it helps

plus Tension on pulley connecting m1 and m2 is 2T