Three blocks of masse m = m, m2 = 2m and m3 = 3m connected by two strings are placed on
horizontal frictionless surface as shown in figure. A horizontal force F is applied to mass m1, The force on mass m2 is
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Answer:
answer in attachment
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2
Answer:
F/3
Explanation:
a(system)=F/m1+m2+m3
a=F/m+2m+3m=)a=F/6m
F(m2)=m2a=)2mxF/6m
F(m2)=F/3
I hope it helps
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