Question

Three blocks of masses 4 kg. 6 kg and 8 kg are bang-
ing over a fixed pulley as shown. The tension in the
the string connecting 4 kg and 6 kg block is :-
(g = 10 m/s)
(1) 4N
(2) 6N

(3) 320/9N
(4)40/9​

Answer 1

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$\tt{\underline{ \underline{ \red{Here,}}}}\\ a = \frac{10g - 8g}{18} \\ \: \: \: \: = \frac{2g}{18} \\ \tt{ \underline{ \underline{ \red{Now,}}}} \\ On \: 4kg \: block, \\ ⇒4g - T = 4a \\ ⇒ 4g - T = 4 \times \frac{2g}{18} \\ ⇒T = 4g - \frac{4g}{9} \\ \: \: \: \: \: \: \: \: \: = \frac{32g}{9} \\ \: \: \: \: \: \: \: \: \: = \frac{320}{9} N$

∵ Option---(3) is corect.

Answer 2

Answer:

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Explanation:

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