Three blocks of masses m, = 4 kg, m = 2 kg, m, = 4 kg are connected with ideal strings passing over a smo
massless pulley as shown in figure. The acceleration of blocks will be (g = 10 m/s2)
Answers
The acceleration of blocks will be 2 m/s² in downword direction.
Explanation:
=> It is given that,
mass of block m₃ = 4 kg
mass of block m₂ = 2 kg
mass of block m₁ = 4 kg
Thus, net mass m = m₁ + m₂ + m₃ = 4 + 2 + 4 = 10 kg
g = 10 m/s²
=> Force :
F = m*g
Force, F₁ = m₁*g = 4 * 10 = 40 N
Force, F₂ = m₂*g = 2 * 10 = 20 N
Force, F₃ = m₃*g = 4 * 10 = 40 N
Total force, F = F₁ + F₂ - F₃
= 40 + 20 - 40
=20 N
=> Acceleration of blocks:
acceleration = total force / net mass
= 20 / 10
= 2 m/s²
Hence, the acceleration of blocks will be 2 m/s² in downword direction.
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