Question

Three blocks of masses m1=10 kg......
Question in the picture

Answer 1

Hello!

It's an easy question to solve!

We know that,
$acceleration = \frac{total \: force}{total \: mass}$
$total \: force = 60n \\ total \: mass \: = 10 + 20 + 30 = 60kg$

$acceleration = \frac{60}{60} \\ = 1nm {s}^{ - 2}$

Tension =>

T1 = M1 a = 10N

F - T2 = (M1 + M2)a
60 - T2 = (10+20)1
30 N = T2

Thanks!

Answer 2

F = m×a

50 = ( m1 + m2 + m3 ) × a

a= 50/ 5+10+15 = 5/3 m/s^2


using quilibrium of forces

F-T1 = ma = ( m1+m2+m3 )a ; T1-T2 =m2a ; T2=m1a
T2= 5× 5/3
T2 = 8.33 N
T1 - 8.33 = 10 × (5/3)
T1 = 25N

now,

(M1 + M2)a = m2g

(12+7)a = 7×9.8

a= 3.61 m/s^2

T= m1aT = 12×3.61 = 43.33 N


hope its helpful :)