Question

Three blocks of masses m1=1kg m2=2kg m3=3kg are connected by mass less string and placed on a horizontal frictionless surface. A force F=12N is applied to mass m1. Calculate the tension T1 between m1 and m2 and T2 between m2 and m3

Answer 1

Answer:

hope it helps you˙˚ʚ(´◡`)ɞ˚˙

Answer 2

To find tension of the system first we have to find 'a'

To find

Formula

F=(m1+m2+m3)a

Now,

F=12N

m1=1kg

m2=2kg

m3=3kg

a=?

so,

12=(1+2+3)a

12=6a

12\6=a

a=2ms-²

Now, find tension

formula

(m2+m3)a

(2+3)2

5×2=10

Hope it helps