Physics, asked by keamo935, 5 months ago

Three blocks of masses m1 = 2 kg, m2 = 4 kg, and m3 = 6 kg are connected by strings on an
inclined plane of 60 as shown. A force of Fapplied = 120 N is applied upwards along the incline
to the uppermost block, causing an upward movement of the blocks along the incline. The
connecting strings are massless.

Answers

Answered by aditi662216
1

Explanation:

Fapplied = 120 N is applied.....

Answered by studay07
1

Answer:

given = m1 = 2kg

             m2 = 4kg

             m3 =  6kg

              θ  =  60°

              f = 120N

to find = accelaration

solution  =

use the newtons second law of ,motion

F -  T2 -Mgsin60° =m3a ----- 1

T2 - T1 -mgsin60° = m2a-----2

T1-T1- mgsinsiii60° = m1a -----3

add all above 3 equations

F- (m1+m2+m3) gsin60° = (m1 +m2 +m3 ) a

120-(2+4+6) 9.8 X √3/2 = (2+4+6)a

a= 1.51 m/s²

the accelaration is a= 1.51 m/s²

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